[mrtg] Re: conversions for MaxBytes
Rippe, Mark (CCI-Warwick)
Mark.Rippe at cox.com
Mon Feb 14 16:40:56 MET 2000
the missing 8k are framing bits.
the t1 proto goes;
1 framing bit 1 framing bit 1 bit 1 bit
8 bits times 24 channels 192 bits 193 bits
1 framing bit 1 bit 1 bit 194 bits
8 bits times 24 channels 192 bits 386 bits
1 framing bit 1 bit 1 bit 387 bits
8 bits times 24 channels 192 bits 579 bits
1 framing bit 1 bit 1 bit 580 bits
8 bits times 24 channels 192 bits 772 bits
1 framing bit 1 bit 1 bit 773.bits
8 bits times 24 channels 192 bits 965 bits
1 framing bit 1 bit 1 bit 966 bits
8 bits times 24 channels 192 bits 1158 bits
1 framing bit 1 bit 1 bit 1159 bits
8 bits times 24 channels 192 bits 1351 bits
1 framing bit 1 bit 1 bit 1352 bits
8 bits times 24 channels 192 bits 1544 bits
mark.rippe at cox.com
"Elegance is for Tailors!"
Albert Einstein on mathematics
> -----Original Message-----
> From: Alex van den Bogaerdt [SMTP:alex at slot.hollandcasino.nl]
> Sent: Monday, February 14, 2000 10:11 AM
> To: CCongdon at WorkNET.net
> Cc: mrtg at list.ee.ethz.ch
> Subject: [mrtg] Re: conversions for MaxBytes
>
> Congdon, Christopher wrote:
> >
> > Acutally, I'd like to know where 1.544 comes from. From what I
> understand, a
> > T1 is composed of 24 64Kb channels. That makes 1.536. I would like to
> know
> > where the extra 8K comes from!
>
> I think it is the other way around... If you provide 24 channels, you
> need a signalling protocol. Just an assumption: this takes 8k ?
>
> If I use an E1 interface to provide 64k ISDN channels I get a total
> of 30 B channels and 1 D channel, 64k each. In this case, 64k gets lost.
>
> regards,
> --
> __________________________________________________________________
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