[mrtg] Re: mult. CPU

[Jerry Heidtke]

MRTG uses normal mathematical precedence. Therefore, your example, which
is like:

A + B + C + D / 4

Will evaluate the same as A + B + C + ( D / 4 )

What you want is ( A + B + C + D ) / 4

Just use parenthesis appropriately in your target line. Make sure to
have white space around every operator, and indent continuation lines.
For example,

Target[mccubeapp02-cpu]:
  ( 
 
.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1.48&.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1
.48:public at 192.168.27.27
  + 
 
.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1.49&.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1
.49:public at 192.168.27.27
  + 
 
.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1.50&.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1
.50:public at 192.168.27.27
  + 
 
.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1.51&.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1
.51:public at 192.168.27.27
  ) 
  / 4

HTH
Jerry

-----Original Message-----
From: fluhmann at vvm.com [mailto:fluhmann at vvm.com] 
Sent: Tuesday, July 01, 2003 4:15 PM
To: mrtg at list.ee.ethz.ch
Subject: [mrtg] mult. CPU


Quick question.  I haven't had to add targets together until now.  I am
adding 4 processors to get a total CPU usage.  Here's a sample:

### CPU Utilization

Target[mccubeapp02-cpu]:
.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1.48&.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1
.48:public at 192.168.27.27
+
.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1.49&.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1
.49:public at 192.168.27.27
+
.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1.50&.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1
.50:public at 192.168.27.27
+
.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1.51&.1.3.6.1.4.1.311.1.1.3.1.1.2.1.3.1
.51:public at 192.168.27.27
/ 4
Title[mccubeapp02-cpu]: CPU Utilization (average)
PageTop[mccubeapp02-cpu]: <h1>McCubeApp02 CPU Utilization </h1>
#AbsMax[mccubeapp02-cpu]: 400
MaxBytes[mccubeapp02-cpu]: 100
#Factor[mccubeapp02-cpu]: .25
Options[mccubeapp02-cpu]: gauge, growright, nopercent, noo, unknaszero
YLegend[mccubeapp02-cpu]: CPU Usage (%)
ShortLegend[mccubeapp02-cpu]: %
Legend1[mccubeapp02-cpu]: Total CPU Usage
LegendI[mccubeapp02-cpu]: TotalCPU:

My question is, is this right?  If I divide at the end, does it divide
the
total by 4 or just the last target?  My other option was to have a
factor
of 1/4.  Factor[xx]: .25 (it's commented out above).  Please let me know
if there are other flaws in my config.  I've strictly been dealing with
routers until now.

Thanks,
Jeremy Fluhmann
McLane Information Systems


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