[rrd-users] [Fwd: Re: Re: Calculating average when aggregating]

[Stephan Harren]

-------- Original Message --------
Subject: Re: [rrd-users] Re: Calculating average when aggregating
Date: Mon, 05 Aug 2002 15:26:11 +0200
From: Stephan Harren <sh at abovenet.de>
To: Geert van der Ploeg <rrd at geert.triple-it.nl>
References: <3D4E3C47.20602 at abovenet.de> 
<00a301c23c5e$6896c960$d201a8c0 at peasant> <3D4E4315.2090102 at abovenet.de> 
<012101c23c74$91274ce0$d201a8c0 at peasant> <3D4E72F5.1030309 at abovenet.de> 
<020401c23c81$9cf19140$d201a8c0 at peasant>



 > What is your way of averaging?
 > We should be able to determine what the outcome should be, following the
 > calculation.
 >
 >
 > If the average does not start at the beginning and doesn't do the
 > calculation right, a (nasty) solution would be to change the UNKNOWN 
value
 > to the value of the 'known' DS.
 > Thus, you get an average which is equal to the only known DS, as long 
as the
 > other, UNKNOWN DS is unknown.
 > That would be something like: ds1,UN,ds0,ds1,IF (where ds1 is the 
unkwown,
 > newest DS, and ds0 the DS that started 6 months ago)
 >
 >
WOW, cool! But as you said, nasty. Anyway, this is not very handy if
you've got twelve datasources ...

O.K., my way of averaging would be like:

			DS1		DS2	  	 AGGREGATED		

Timestamp1:
	20		NaN			20
Timestamp2:
	10		NaN			10
Timestamp3:
	20		10			30

Sum of the three timestamps is 60 so the average should be 20								
If the Print-Command behaves like the graphing it will look like this:

			DS1		DS2	  	AGGREGATED		

Timestamp1:
	20		NaN			NaN
Timestamp2:
	10		NaN			NaN
Timestamp3:
	20		10			30

There is only one valid timestmp, so the average will be 30.

Have you ever tried this ?

Best regards,

Stephan
-- 
Stephan Harren
Manager Site Operations
MFN-IS Germany
Tel 	0049 69 90554 153
Cell
0049 173 7011126
Fax
0049 69 90554 111


-- 
Stephan Harren
Manager Site Operations
MFN-IS Germany
Tel 	0049 69 90554 153
Cell 
0049 173 7011126
Fax 
0049 69 90554 111

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