[rrd-users] Re: extracting data from .rrd files

[Emmanuel Muncal]

Sir:

I tried your perl line: Heres my result:

# perl -n -e 'printf ("%s %s\n", $1, $2) if (s/(\d{9,10}) .*
([\d.e+\-]{16})/)'    \

<mysample.rrd > file.txt

Substitution replacement not terminated at -e line 1.


How do you convert your values ? I get an exponential values in XML
file using the rrdtool dump.

Kindly excuse my questions Im just starting. =)

Thank you very much.

On Mar 25, 2005 1:20 AM, Martin Schuster <schuster at isja.org> wrote:
> On Thu, Mar 24, 2005 at 04:11:45PM -0500, D.Walsh wrote:
> > I have examined "rrdtool dump filename >outfile.xml", problem is the
> > data recovered is hard to understand since I am trying to edit this
> > data and correct or add missing data and I was hoping for something in
> > a human-readable format.
> >
> > If HR is not an possible option, how do I interpret the following so I
> > can make the changes I require?
> >
> >                       <!-- 2005-03-21 18:00:00 EST / 1111446000 --> <row><v>
> > 0.0000000000e+00 </v></row>
> >                       <!-- 2005-03-21 18:30:00 EST / 1111447800 --> <row><v>
> > 2.7777777778e-03 </v></row>
> >
> at 2005-03-21 18:00:00 EST (1111446000 seconds since 1970-01-01 00:00),
>    the value was 0
> at 2005-03-21 18:30:00 EST (1111447800 seconds since 1970-01-01 00:00),
>    the value was 2.778e-03, thats 0.002778
> how much more readable do you want it? :)
> 
> If you need simple time:value pairs, you could do sth like
> perl -n -e 'printf ("%s %s\n", $1, $2) if (s/(\d{9,10}) .* ([\d.e+\-]{16})/)' \
>     < file.rrd > file.txt
> (untested :)
> --
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> |  <Douglas at karanet.at>  ICQ# 20511117    "Linux!"  is the answer  /(   )\
> +--------------------------------------------------------------*    ^^-^^
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-- 
Regards,

Emmanuel Muncal, ECE

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