[rrd-users] Re: Data differ from RRA to RRA - normal?

Alex van den Bogaerdt alex at ergens.op.het.net
Thu Oct 12 15:40:04 MEST 2006

On Thu, Oct 12, 2006 at 03:03:05PM +0200, Heiko Teichmann wrote:

> > Each time an interval is computed, it is fed to every RRA.  When an
> > RRA has enough data to generate a new row, it will do so.

> Did that mean that even the RRA with the large pdp_per_row (288) stores 
> the data for the 288 steps and computes then the new row for the RRA? If 
> so what would be the divisor for the average computing if some data 
> failing (e.g. 2 steps fails -> 286 data points available all with the 
> same value; Question: average = (286*x)/288 or (286*x)/286 )?

I believe the answer to be (286*x)/286.  Shouldn't be hard
to verify in an experiment.

Alex van den Bogaerdt

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