[rrd-users] Actual interpolation method
Macckone at aol.com
Macckone at aol.com
Wed Apr 8 02:22:16 CEST 2009
I am looking for a description of the actual interpolation method used to
convert data points to RRAs in the specific case of 1:1 correspondence.
Rate generation data:
920805000:10
920805300:20
920805600:10
920805900:10
Generated data:
920805000:000
920805300:3000
920805600:9000
920805900:12000
Example data:
920805000:000
920805305:3100
920805603:9030
920805907:12070
RRD results:
<!-- 1999-03-07 05:10:00 CST / 920805000 -->
<row><v> NaN </v></row>
<!-- 1999-03-07 05:15:00 CST / 920805300 --> <row><v> 1.0163934426e+01
</v></row>
<!-- 1999-03-07 05:20:00 CST / 920805600 --> <row><v> 1.9737072285e+01
</v></row>
<!-- 1999-03-07 05:25:00 CST / 920805900 --> <row><v> 1.0098993289e+01
</v></row>
The first data point is what would be expected.
ie. 3100/305.= 10.163934426
For the additional data point:
5930/298 = 19.899328859
Then it look like we first interpolate the data point for
92805300 = 3049.1803279
That gives
5980.8197213/303=19.738678948
Which is close but still differs in the 5th decimal place.
If we do a full second degree interpolation:
92805300 = 3049.1803279
92805600 = 19.899328859*295+3100 = 8970.302013405
So
8970.302013405-3049.1803279=5921.1216855
5921.1216855/300 = 19.737072285
This seems to be what is done but I have not seen a description anywhere.
Is this indeed what is done?
First interpolating the data points and then calculating the slope?
The final data point below seems to confirm this.
Could this be added to the FAQ or the documentation some where?
Mack
Ammendum:
For the final data point.
3040/304=10
92805900 = 10*297+9030 =12000
12000-8970.302013405=3029.697986595
3029.697986595/300=10.098993289
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