[rrd-users] Consolidated Funaction

[Matt Chung]

Hey Ahamad,
Presumably, if I understand correctly, you would like to retrieve the
maximum value of each individual datasource and represent it graphically
correct?

If so, the first thing you would need to do is to define your data
definitions when using rrdtool graph:
DEF:datasource1=myrrd.rrd:DS1:MAXIMUM
DEF:datasource2=myrrd.rrd:DS2:MAXIMUM
DEF:datasource3=myrrd.rrd:DS3:MAXIMUM

Then, in order to extract the maximum for the datasources respectively, you
could use VDEF:
VDEF:maxdatasource1=datasource1:MAXIMUM
VDEF:maxdatasource2=datasource2:MAXIMUM
VDEF:maxdatasource2=datasource2:MAXIMUM

You can use those VDEFs as variables in other calculations if you would like
as well, or simply output those values on the graph.
I hope this helps,
Matt Chung

On Mon, May 17, 2010 at 11:13 PM, Shameem Ahamed
<shameem.ahamed at yahoo.com>wrote:

> Hi,
>
> I have a RRD which stores multiple DS in a single rrd file. Currently I am
> storing 10 DS in a single file. The create function also defines 5 RRA with
> CF as MAX (to find out the maximum of each DS ). I have attached the pseudo
> code below.
>
> DS:DS1:COUNTER
> DS:DS2:COUNTER
> DS:DS3:COUNTER
> DS:DS4:COUNTER
> DS:DS5:COUNTER
> DS:DS6:COUNTER
> DS:DS7:COUNTER
> DS:DS8:COUNTER
> DS:DS9:COUNTER
> DS:DS10:COUNTER
> RRA:MAX:0:1:3
> RRA:MAX:0:12:3
> RRA:MAX:0:288:3
> RRA:MAX:0:2016:3
> RRA:MAX:0:60480:3
>
>
> My doubt is, If I issue a fetch command
>
> fetch out.rrd MAX -r 300 -e (int(time()/300))*300 -s e-900s
>
> Which DS max result will be returned ?.
>
> How can i get the max of respective DS stored in the RRD ?.
>
> Regards,
> Shameem
>
>
>
>
>
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