[mrtg] Re: Satellite consumption

[Emmanuel "Noel" Gabriel]

thanks for your response, but we have two back bone connected into our
router one a leased line from a telco and the other one is the satellite
feed. if i'll be graphing the ether port then i'll be getting integral of
two bandwidth. but that give me an idea, how about subtracting the other one
to get the exact bandwidth consumption. how to do mathematical operation on
mrtg?

thanks,

====================================
L      L      Emmanuel "Noel" Gabriel        .~.
LL  LL      MosCom Tarlac - SysAd         /\/\
LLLLL      http://www.tarlac.com              //  \\
LLLLL      0919 - 343-6125                     /(   )\
==============================^^-^^===

----- Original Message -----
From: "Andrew" <awd at awd.aust.to>
To: "Emmanuel "Noel" Gabriel" <noel at tarlac.com>
Sent: Saturday, July 08, 2000 11:23 AM
Subject: Re: [mrtg] Satellite consumption


>
> ----- Original Message -----
> From: "Emmanuel "Noel" Gabriel" <noel at tarlac.com>
> To: "MRTG mailing list" <mrtg at list.ee.ethz.ch>
> Sent: Saturday, July 08, 2000 11:16 AM
> Subject: [mrtg] Satellite consumption
>
>
> > Hi to all,
> >
> > i'm monitoring one of our serial port which is connected into a
satellite
> > modem. the bandwidth for this connection is 4.8Mbps but we are 20 who
are
> > sharing to this one satellite, so what i'm getting into the mrtg graph
is
> > the whole consumption of all of the 20 pops who are sharing with the
> > satellite link.
> >
> > 20 pops are pointing into one bird and all of the pops are sharing with
> > 4.8Mbps, there's is no CIR. so this mean you can get the whole 4.8 and
> since
> > signal are beamed to us in multicast, you can't guarantee that what
> you're
> > getting on the graph is all yours and not packets for outher pops.
> >
> > Is there's a way that i could only graph my total consumption and not
the
> > total consumption of the bandwidth?
> monitor the ethernet on your router not your serial port :)
> stuff for ethernet is just for ur network!!
> HTH
> cya
> Andrew
>


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