[mrtg] Re: Utilization graphs

[alex at ergens.op.Het.Net]

Paul C. Williamson wrote:

> Has anyone written a script to "discover" the busiest units over a per
> iod of time?  I have about 300 routers, all being graphed, and I'd lik
> e to have a summary page that shows me the 5 most busy and 5 least bus
> y routers.  I would think since all the graphs are derived from number
> s, I could run a perl script from a cron job at midnight giving me the
> information I need for the next business day.  I am running Red Hat 6.
> 1 and mrtg 2.8.11.  If anyone has advice, I'm all ears.

If there's enough processing power and time available:

1) calculate start and end times in seconds-since-epoch format
2) scan each log file; for each line with a time stamp inbetween the
   two values derived from step 1: add up the value found in column 2.
   Do the same with column 3.  Write the result to a file
3) sort the file (numeric mode)
4) "head -5" and "tail -5" provide the information you need

regards,
-- 
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