[mrtg] Re: Using MRTG for graphing sum of OIDS.
PAUL WILLIAMSON
pwilliamson at mandtbank.com
Mon Feb 14 17:21:44 MET 2005
Look at the docs:
Target[ezwf]: OID1&OID2 + OID3&OID4:communitystring at host
results essentially in:
OID1+ OID3 = value 1
OID2 + OID4 = value 2
Paul
>>> "G. Colangelo" <binarym at psycho-hazard.net> 2/14/2005 10:26:22 AM >>>
Hi,
I want my mrtg to graph UCD-SNMP-MIB::memAvailReal +
UCD-SNMP-MIB::memBuffer + UCD-SNMP-MIB::memCac hed", so i tried the
following syntax:
Target[mem]: 1.3.6.1.4.1.2021.4.6.0 + 1.3.6.1.4.1.2021.4.15.0
+ 1.3.6.1.4.1.2021.4.14.0&1.3.6.1.4.1.2021.4.6.0:comm at host (no linefeed,
space between each '+')
But mrtg reply me this:
[root at rei]:/etc# mrtg
16:07 ERROR: Target[mem][_IN_] '1.3.6.1.4.1.2021.4.6.0 +
1.3.6.1.4.1.2021.4.15.0 + $target->[3]{$mode} ' (warn): Argument
"\x{1}\x{3}..." isn't numeric in addition (+) at (eval 12) line 1.
ERROR: Target[mem][_OUT_] '1.3.6.1.4.1.2021.4.6.0 +
1.3.6.1.4.1.2021.4.15.0 + $target->[3]{$mode} ' (warn): Argument
"\x{1}\x{3}..." isn't numeric in addition (+) at (eval 13) line 1.
I tried a lot of differents syntax, but none works.
I don't understand the syntax used in the manpage:
oid1&oid2:comm at host / oid3&oid4:comm at host * x
Why is there 3 '&'. I was believing that '&' was used as delimiter
between in and out sources.
Can anybody explain me the syntax to do it ?
Regards,
--
Gérald Colangelo
binarym at psycho-hazard.net - http://psycho-hazard.net/~binarym/
Being a sysadmin means hours of hard labor every day.
Being an abusive sysadmin means hours of fun.
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