[mrtg] 64-bit counters with SNMPv1?

[Stuart Kendrick]

hi forthofer,

i don't have an answer for you, this is just a ramble:

i find this puzzling.  i thought that one of the few differences between 
SNMPv1 and SNMPv2c was support for 64-bit counters.  and yet, you seem 
to be retrieving the value of a 64 bit counter, using an SNMPv1 GET

what are you getting, when you issue your v1 request for this 64bit 
counter?  just 32 bits of the full 64 bits?  curiousity ...

i would be surprised if this box supported only v1

that being said, i've run into a manufacturer (NetApp) which supports 
only v1 ... however, they provide access to 64 bit counters by providing 
two variables for each counter, e.g. miscHighNetRcvdBytes and 
miscLowNetRcvdBytes ... where the High counter contains the top 32 bits 
and the Low counter contains the bottom 32 bits.  i retrieve both and 
perform a string concatenation, all done in MRTG's Target line.  if 
Nortel does only support v1, perhaps they also support some scheme like 
this, in order to deliver access to 64 bit counters.  this would be 
visible in one of their enterprise MIBs

--sk


Forthofer Russ wrote:
> I have a device (a Nortel OM3500) which has high-speed interfaces.  So, 
> I need to retrieve traffic counts using ifHCInOctets, etc….i.e., 64-bit 
> counters.   It appears to me that MRTG uses the 64-bit counters when 
> SNMPv2 is used.  However, in this case, v2 is apparently not supported.  
> To verify this, I entered the following commands:
> 
> snmpget -c commstr -v 2c xx.xx.xx.xx 1.3.6.1.2.1.31.1.1.1.6.17   
> (response: Timeout: No Response from xx.xx.xx.xx)
> 
> snmpget -c commstr -v 1 xx.xx.xx.xx 1.3.6.1.2.1.31.1.1.1.6.17  
> (response: IF-MIB::ifHCInOctets.17 = Counter64: 6058121224)
> 
> This suggests to me that the box does not support SNMPv2.  Is there a 
> way for me to make use of the 64-bit  counters, while using SNMPv1?  (Or 
> if someone knows of a way to enable SNMPv2 on a Nortel OM3500, that 
> would also be a quite acceptable - perhaps preferable -  solution.)
> 
> Any help would be greatly appreciated.
> 
> Russ
> 
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