[rrd-users] Re: using resolution on rrdtool fetch

[Darren/Torin/Who Ever...]

Alex van den Bogaerdt, in an immanent manifestation of deity, wrote:
>This will almost always result in a time series that is NOT
>in the RRA. Therefore the highest resolution RRA will be chosen
>which is not what you want.
>
>Make sure that
>a) both start and end time are a multiple of 1800
>b) both start and end time are within the RRA
>
>So: if time now is called "t", do end time == int(t/1800)*1800,
>start time == end time -1d, resolution == 1800.

Wow.  That's exactly what I needed.  It works..

Thanks,
  Darren
-- 
<torin at daft.com><http://www.daft.com/~torin/> <torin at debian.org><perl at slut.org>
Darren Stalder/2608 Second Ave, @282/Seattle, WA 98121-1212/USA/+1-206-ELF-LIPZ
@		     Make a little hot-tub in your soul.		      @

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