[rrd-users] Re: Newbie problem

Steve Robb steve_robb at cnt.com
Sun Mar 16 17:04:43 MET 2003

>Why 3600, if it's five minutes?  Wouldn't it be divided by 300?  And 
>even if the right divisor is 3600, how do I get a value less than 
>2.7e-04 (but larger than 0), if I'm only giving it integers.

Ooops...I've been working with hourly graphs too much lately. ;-)

You're right - it should be a factor of 300, NOT 3600.

>rrdtool create foo.rrd DS:incoming:COUNTER:600:0:U RRA:AVERAGE:0.5:1:300 
>RRA:AVERAGE:0.5:24:120 RRA:AVERAGE:0.5:288:400 DS:reject:COUNTER:600:0:U 
>RRA:MAX:0.5:1:300 RRA:AVERAGE:0.5:24:120 RRA:AVERAGE:0.5:288:400

Since you've defined your DS as a COUNTER, it will store the difference
between this reading and the previous one which may give you a very small
number. So instead of storing the value you want, its storing the delta. Try
defing it as an ABSOLUTE and see what happens.


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