[rrd-users] Re: Newbie problem

[David Corbin]

Why 3600, if it's five minutes?  Wouldn't it be divided by 300?  And 
even if the right divisor is 3600, how do I get a value less than 
2.7e-04 (but larger than 0), if I'm only giving it integers.

Steve Robb wrote:

>Think of it this way, if you have a measurement of 10 units in a 5 minute
>period you think you would have the value 10 stored but the per second rate
>would actually be 10/3600 = 2.7e-03. That's the value that gets stored since
>everything gets stored as a per second rate.
>
>MAX and LAST won't change the stored value, just the way it's aggregated.
>
>Steve Robb
>
>
>  
>


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