[rrd-users] Re: Newbie problem
dcorbin at machturtle.com
Sun Mar 16 15:51:38 MET 2003
Why 3600, if it's five minutes? Wouldn't it be divided by 300? And
even if the right divisor is 3600, how do I get a value less than
2.7e-04 (but larger than 0), if I'm only giving it integers.
Steve Robb wrote:
>Think of it this way, if you have a measurement of 10 units in a 5 minute
>period you think you would have the value 10 stored but the per second rate
>would actually be 10/3600 = 2.7e-03. That's the value that gets stored since
>everything gets stored as a per second rate.
>MAX and LAST won't change the stored value, just the way it's aggregated.
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