[rrd-users] Re: Help with Bash script to calc end-time in multiples of 300 ?

[Simon Hobson]

Alex van den Bogaerdt wrote:

>  > etime=`date +%s`
>>  step=300
>>  etime=$(( ${etime} - ( ${etime} % ${step} ) ))
>
>etime=$(( ${etime} / ${step} * ${step}  ))
>
>is 10% faster, at least on my system. I tried this by looping 100,000
>times doing those calculations, several runs.  Bash uses integer
>calculations, and my sequence saves a calculation internally.

Fair enough.

>Printing the value can be done using perl, but unless you're going to
>use perl for other purposes as well you are better off with gnu-date.
>This runs in 44% of the time needed for starting perl:
>
>/bin/date -d 19700101\ 00:00\ +0000\ ${etime}sec
>
>It means: the unix epoch (19700101 00:00, timezone UTC) and then
>${etime} seconds further in time (so: reverse of date +%s)

Sneeky ! I'd never have thought of that.

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