[mrtg] Re: 14all.cgi and too high graph.

Rainer Bawidamann Rainer.Bawidamann at rz.uni-ulm.de
Tue Nov 14 11:16:57 MET 2000


In article <sa101dba.025 at mailint.commcare.ch>,
	Peter.Baumann at commcare.ch ("Peter Baumann") writes:

> I have a strange behavior of 14all.cgi and the data entered in the
> router.rrd file. Today a customer had an break of his line and I
> couldn't monitor his router anymore. He have a 128 Kbps line and in
> the rrd-file I have a limitation setup of 128 Kbps
> ->
>                 <name> ds0 </name>
>                 <type> COUNTER </type>
>                 <minimal_heartbeat> 86400 </minimal_heartbeat>
>                 <min> NaN </min>
>                 <max> 1.2800000000e+05 </max>
> 
> Now today at 13:25:00 I had a "normal" traffic value. and at 13:30 the
> values where right limited (100Kbps). Now my questions:
> 
> - Why is it not going to exactly 128Kbps as specified in the rrd file.

There might be some protocol overhead so 128.000 bps data transfer rate
are never reached.

> - Why is 14all.cgi script displaying a 800Kbps ! peak (rectangle
>   block) in the browser.

It looks like you have Options:bits set while monitoring bits allready.
Do you query the normal ifInOctets/ifOutOctets?

>                         <!-- 2000-11-13 13:25:00 CET --> <row><v> 4.3639310752e+03 </v><v> 1.8112786889e+03 </v></row>
>                         <!-- 2000-11-13 13:30:00 CET --> <row><v> 1.0012343550e+05 </v><v> 1.7800380952e+03 </v></row>
>                         <!-- 2000-11-13 13:35:00 CET --> <row><v> 1.0012343550e+05 </v><v> 1.7800380952e+03 </v></row>
>                         <!-- 2000-11-13 13:40:00 CET --> <row><v> 1.0012343550e+05 </v><v> 1.7800380952e+03 </v></row>
>                         <!-- 2000-11-13 13:45:00 CET --> <row><v> 1.0012343550e+05 </v><v> 1.7800380952e+03 </v></row>
>                         <!-- 2000-11-13 13:50:00 CET --> <row><v> 1.0012343550e+05 </v><v> 1.7800380952e+03 </v></row>

This shows that the log file contains bits per second. So if you have
"options: bits" set you will get these multiplied by 8.

Rainer
-- 
Rainer.Bawidamann at rz.uni-ulm.de

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